SpyriadisNetworkBlob

Category: SQL Server

  • How to get day of the week from a datetime in SQL Server

    The day of the week can be retrieved in SQL Server by using the DatePart function. The value returned by function is between 1 (Sunday) and 7 (Saturday). To convert this to a string representing the day of the week, use a CASE statement.

    Method 1:
    Create function running following script:

    CREATE FUNCTION dbo.udf_DayOfWeek(@dtDate DATETIME)
RETURNS VARCHAR(10)
AS
BEGIN
DECLARE @rtDayofWeek VARCHAR(10)
SELECT @rtDayofWeek = CASE DATEPART(weekday,@dtDate)
WHEN 1 THEN 'Sunday'
WHEN 2 THEN 'Monday'
WHEN 3 THEN 'Tuesday'
WHEN 4 THEN 'Wednesday'
WHEN 5 THEN 'Thursday'
WHEN 6 THEN 'Friday'
WHEN 7 THEN 'Saturday'
END
RETURN (@rtDayofWeek)
END
GO

    Call this function like this:
    SELECT dbo.udf_DayOfWeek(GETDATE()) AS DayOfWeek
    ResultSet:
    DayOfWeek
    ———-
    Monday

    Method 2:

    SELECT DATENAME(dw, GETDATE())

  • Clear all your SQL Server database with just 6 lines of T-SQL

    This is a SQL Script that Cleans your Database Records & resets Identity Columns, and it is all in 6 lines!

    /*Disable Constraints & Triggers*/
exec sp_MSforeachtable 'ALTER TABLE ? NOCHECK CONSTRAINT ALL'
exec sp_MSforeachtable 'ALTER TABLE ? DISABLE TRIGGER ALL'

/*Perform delete operation on all table for cleanup*/
exec sp_MSforeachtable 'DELETE ?'

/*Enable Constraints & Triggers again*/
exec sp_MSforeachtable 'ALTER TABLE ? CHECK CONSTRAINT ALL'
exec sp_MSforeachtable 'ALTER TABLE ? ENABLE TRIGGER ALL'

/*Reset Identity on tables with identity column*/
exec sp_MSforeachtable 'IF OBJECTPROPERTY(OBJECT_ID(''?''), ''TableHasIdentity'') = 1 BEGIN DBCC CHECKIDENT (''?'',RESEED,0) END'

  • Find the tables that use the most disk space in SQL SERVER

    Simply start a new query window for the database and use the statement below:

    SELECT object_name(i.object_id) as objectName,
i.[name] as indexName,
sum(a.total_pages) as totalPages,
sum(a.used_pages) as usedPages,
sum(a.data_pages) as dataPages,
(sum(a.total_pages) * 8 ) / 1024 as totalSpaceMB,
(sum(a.used_pages) * 8 ) / 1024 as usedSpaceMB,
(sum(a.data_pages) * 8 ) / 1024 as dataSpaceMB
FROM sys.indexes i
INNER JOIN sys.partitions p
ON i.object_id = p.object_id
AND i.index_id = p.index_id
INNER JOIN sys.allocation_units a
ON p.partition_id = a.container_id
GROUP BY i.object_id, i.index_id, i.[name]
ORDER BY sum(a.total_pages) DESC, object_name(i.object_id)
GO